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Kirchhoff's Laws questions

Physics · 3rd secondary (languages) · Electric Current and Electromagnetism · Electric Current, Ohm's Law and Kirchhoff's Laws

Question bank for the lesson "Kirchhoff's Laws" with 118 questions. Pick a set and start: you see at once whether your answer is right and read the explanation. Free, no sign-up.

Lesson questions

Click any question to solve it on the site and see the answer with its explanation.

Multiple choice questions

  1. In the electric network shown, ..........

    Figure of question 1
    1. A the current (I) = 3 A, and its direction is from a to c
    2. B the current (I) = 3 A, and its direction is from c to a
    3. C the current (I) = 5 A, and its direction is from a to c
    4. D the current (I) = 5 A, and its direction is from c to a
    Solve this question →
  2. In the opposite figure, if I1=I2=I3=I4=I5I_1 = I_2 = I_3 = I_4 = I_5, then I6I_6 equals ..........

    Figure of question 2
    1. A I1I_1
    2. B 2I12 I_1
    3. C 3I13 I_1
    4. D 4I14 I_1
    Solve this question →
  3. In the figure shown, the value of I is ..........

    Figure of question 3
    1. A 2 A
    2. B 4 A
    3. C 6 A
    4. D 12 A
    Solve this question →
  4. The opposite figure represents part of an electric circuit, so the value of I is ..........

    Figure of question 4
    1. A 19 A
    2. B 23 A
    3. C 27 A
    4. D 31 A
    Solve this question →
  5. The opposite figure represents part of an electric circuit, so the value of I is ..........

    Figure of question 5
    1. A 2 A
    2. B 4 A
    3. C 6 A
    4. D 8 A
    Solve this question →
  6. The opposite figure represents part of an electric circuit, so the value of I is ..........

    Figure of question 6
    1. A 2.5 A
    2. B 3.5 A
    3. C 6.5 A
    4. D 7.5 A
    Solve this question →
  7. In the opposite figure:
    the current I1I_1 is ..........

    Figure of question 7
    1. A -2.5 A
    2. B 3.5 A
    3. C 4 A
    4. D 6 A
    Solve this question →
  8. In the opposite figure:
    the current I2I_2 is ..........

    Figure of question 8
    1. A -2.5 A
    2. B 3.5 A
    3. C 4 A
    4. D 6 A
    Solve this question →
  9. A metal ring is connected in an electric circuit and currents flow through it as in the opposite figure, so:
    the current I1I_1 is ..........

    Figure of question 9
    1. A 0
    2. B 4 A
    3. C 9 A
    4. D 13 A
    Solve this question →
  10. A metal ring is connected in an electric circuit and currents flow through it as in the opposite figure, so:
    the current I2I_2 is ..........

    Figure of question 10
    1. A 2 A
    2. B 4 A
    3. C 9 A
    4. D 12 A
    Solve this question →
  11. In the opposite figure, if the potentials of points B, C, D are: potential of B = 4 V, potential of C = 10 V and potential of D = 6 V, then the potential of point A equals ..........

    Figure of question 11
    1. A 4 V
    2. B 8 V
    3. C 12 V
    4. D 16 V
    Solve this question →
  12. The opposite figure is part of an electric circuit showing the potential of some points, so the current flowing between the two points (x), (y) shown on the figure equals ..........

    Figure of question 12
    1. A 1 A
    2. B 4 A
    3. C 5 A
    4. D 6 A
    Solve this question →
  13. The opposite figure represents part of a closed electric circuit. If each resistance is 3 Ω, the value of V1V_1 is ..........

    Figure of question 13
    1. A 10 V
    2. B 20 V
    3. C 15 V
    4. D 12 V
    Solve this question →
  14. In the opposite figure, the correct order of the potentials at points x, y, z is ..........

    Figure of question 14
    1. A Vx>Vy>VzV_x > V_y > V_z
    2. B Vy>Vx>VzV_y > V_x > V_z
    3. C Vz>Vx>VyV_z > V_x > V_y
    4. D Vx>Vz>VyV_x > V_z > V_y
    Solve this question →
  15. In the circuit shown, the values are ..........

    Figure of question 15
    1. A V1V_1 = 4 V, V2V_2 = 10 V
    2. B V1V_1 = 4 V, V2V_2 = 7 V
    3. C V1V_1 = 10 V, V2V_2 = 10 V
    4. D V1V_1 = 10 V, V2V_2 = 7 V
    Solve this question →
  16. In the electric circuit shown, the voltmeter reading is ..........

    Figure of question 16
    1. A 20 V
    2. B 15 V
    3. C 5 V
    4. D 0
    Solve this question →
  17. In the circuit shown, the values of the power (Pw)x(P_w)_x, (Pw)y(P_w)_y are ..........

    Figure of question 17
    1. A (Pw)x(P_w)_x = 4 W, (Pw)y(P_w)_y = 12 W
    2. B (Pw)x(P_w)_x = 12 W, (Pw)y(P_w)_y = 4 W
    3. C (Pw)x(P_w)_x = 16 W, (Pw)y(P_w)_y = 12 W
    4. D (Pw)x(P_w)_x = 4 W, (Pw)y(P_w)_y = 14 W
    Solve this question →
  18. The opposite figure represents part of an electric circuit, so the voltmeter reading is ..........

    Figure of question 18
    1. A 20 V
    2. B 15 V
    3. C 5 V
    4. D 1 V
    Solve this question →
  19. The opposite figure represents part of an electric circuit carrying an electric current, so the value of VBV_B is ..........

    Figure of question 19
    1. A 20 V
    2. B 30 V
    3. C 40 V
    4. D 50 V
    Solve this question →
  20. The opposite figure represents part of an electric circuit, so the emf VBV_B equals ..........

    Figure of question 20
    1. A 3 V
    2. B 4 V
    3. C 6 V
    4. D 8 V
    Solve this question →
  21. In the electric circuit shown in the figure, if the potential difference between points A, B is 4 V, then the resistance R equals ..........

    Figure of question 21
    1. A 5 Ω
    2. B 10 Ω
    3. C 15 Ω
    4. D 20 Ω
    Solve this question →
  22. In the circuit shown in the figure, if R = 7.5 Ω, then the potential difference between points a, b equals ..........

    Figure of question 22
    1. A 0
    2. B 5 V
    3. C 10 V
    4. D 15 V
    Solve this question →
  23. In the opposite electric circuit, if the reading of each of the three ammeters is zero and all batteries have negligible internal resistance, then the two emfs (VB)1(V_B)_1, (VB)2(V_B)_2 are ..........

    Figure of question 23
    1. A (VB)1(V_B)_1 = 5 V, (VB)2(V_B)_2 = 10 V
    2. B (VB)1(V_B)_1 = 10 V, (VB)2(V_B)_2 = 5 V
    3. C (VB)1(V_B)_1 = 5 V, (VB)2(V_B)_2 = 15 V
    4. D (VB)1(V_B)_1 = 15 V, (VB)2(V_B)_2 = 5 V
    Solve this question →
  24. In the opposite electric circuit:
    the current I1I_1 equals ..........

    Figure of question 24
    1. A 1 A
    2. B 2 A
    3. C 3 A
    4. D 4 A
    Solve this question →
  25. In the opposite electric circuit:
    the current I2I_2 equals ..........

    Figure of question 25
    1. A 1 A
    2. B 2 A
    3. C 3 A
    4. D 4 A
    Solve this question →
  26. The opposite figure shows a closed electric circuit. The resistance carrying the largest current is ..........

    Figure of question 26
    1. A R1R_1
    2. B R2R_2
    3. C R3R_3
    4. D R1R_1, R2R_2
    Solve this question →
  27. In the opposite electric circuit, if the ammeter reading is (I), then its reading when:
    only switch (K1)(K_1) is closed is ..........

    Figure of question 27
    1. A I
    2. B I2\dfrac{I}{2}
    3. C 2I
    4. D 4I
    Solve this question →
  28. In the opposite electric circuit, if the ammeter reading is (I), then its reading when:
    only switch (K2)(K_2) is closed is ..........

    Figure of question 28
    1. A I
    2. B I2\dfrac{I}{2}
    3. C 2I
    4. D 4I
    Solve this question →
  29. In the opposite electric circuit, if the ammeter reading is (I), then its reading when:
    both switches (K1)(K_1), (K2)(K_2) are closed is ..........

    Figure of question 29
    1. A I
    2. B I2\dfrac{I}{2}
    3. C 2I
    4. D 4I
    Solve this question →
  30. In the circuit shown, if the ammeter reading is 4 A and the voltmeter reading is 3 V, then the emf (VB)(V_B) equals ..........

    Figure of question 30
    1. A 4 V
    2. B 6 V
    3. C 10 V
    4. D 14 V
    Solve this question →
  31. In the opposite electric circuit, if the ammeter reading is 1 A and the voltmeter reading is 10 V, then the two resistances (R1)(R_1), (R2)(R_2) are ..........

    Figure of question 31
    1. A R1R_1 = 10 Ω, R2R_2 = 5 Ω
    2. B R1R_1 = 30 Ω, R2R_2 = 2 Ω
    3. C R1R_1 = 20 Ω, R2R_2 = 10 Ω
    4. D R1R_1 = 20 Ω, R2R_2 = 2 Ω
    Solve this question →
  32. From the opposite circuit:
    the current I1I_1 equals ..........

    Figure of question 32
    1. A 4.01 A
    2. B 8.02 A
    3. C 0.77 A
    4. D 1.11 A
    Solve this question →
  33. From the opposite circuit:
    the current I2I_2 equals ..........

    Figure of question 33
    1. A 0.77 A
    2. B 4.01 A
    3. C 8.02 A
    4. D 1.11 A
    Solve this question →
  34. From the opposite circuit:
    the emf VBV_B equals ..........

    Figure of question 34
    1. A 2.01 V
    2. B 4.03 V
    3. C 6.01 V
    4. D 8.02 V
    Solve this question →
  35. From the electric circuit shown:
    the current through resistor R1R_1 is ..........

    Figure of question 35
    1. A 0.22 A
    2. B -0.23 A
    3. C 0.45 A
    4. D 0.53 A
    Solve this question →
  36. From the electric circuit shown:
    the current through resistor R2R_2 is ..........

    Figure of question 36
    1. A 0.22 A
    2. B -0.23 A
    3. C 0.45 A
    4. D 0.53 A
    Solve this question →
  37. From the electric circuit shown:
    the current through resistor R3R_3 is ..........

    Figure of question 37
    1. A 0.22 A
    2. B -0.23 A
    3. C 0.45 A
    4. D 0.53 A
    Solve this question →
  38. From the circuit shown in the figure:
    the emf (VB)1(V_B)_1 is ..........

    Figure of question 38
    1. A 5 V
    2. B 8 V
    3. C 15 V
    4. D 20 V
    Solve this question →
  39. From the circuit shown in the figure:
    the emf (VB)2(V_B)_2 is ..........

    Figure of question 39
    1. A 5 V
    2. B 8 V
    3. C 10 V
    4. D 12 V
    Solve this question →
  40. From the circuit shown in the figure:
    the potential difference between points b, e is ..........

    Figure of question 40
    1. A 5 V
    2. B 6 V
    3. C 7 V
    4. D 8 V
    Solve this question →
  41. In the opposite electric circuit, the ammeter reads 2 A. When switch K is closed at position (1), the ammeter reads 2.2 A, and when switch K is closed at position (2), the ammeter reads 1.81 A, so:
    the emf of the battery (VB)1(V_B)_1 is ..........

    Figure of question 41
    1. A 20 V
    2. B 22 V
    3. C 18 V
    4. D 16 V
    Solve this question →
  42. In the opposite electric circuit, the ammeter reads 2 A. When switch K is closed at position (1), the ammeter reads 2.2 A, and when switch K is closed at position (2), the ammeter reads 1.81 A, so:
    the resistance (R) equals ..........

    Figure of question 42
    1. A 3 Ω
    2. B 6 Ω
    3. C 2 Ω
    4. D 12 Ω
    Solve this question →
  43. In the opposite electric circuit, the ammeter reads 2 A. When switch K is closed at position (1), the ammeter reads 2.2 A, and when switch K is closed at position (2), the ammeter reads 1.81 A, so:
    the emf of the battery (VB)2(V_B)_2 is approximately ..........

    Figure of question 43
    1. A 12 V
    2. B 14 V
    3. C 16 V
    4. D 18 V
    Solve this question →
  44. Using Kirchhoff's two laws in the circuit shown: (note that the directions marked on the figure are assumed directions and not necessarily the true current directions)
    the current I1I_1 is ..........

    Figure of question 44
    1. A 0.36 A
    2. B 0.6 A
    3. C -0.36 A
    4. D -0.6 A
    Solve this question →
  45. Using Kirchhoff's two laws in the circuit shown: (note that the directions marked on the figure are assumed directions and not necessarily the true current directions)
    the current I2I_2 is ..........

    Figure of question 45
    1. A 0.96 A
    2. B 0.6 A
    3. C -0.96 A
    4. D -0.6 A
    Solve this question →
  46. Using Kirchhoff's two laws in the circuit shown: (note that the directions marked on the figure are assumed directions and not necessarily the true current directions)
    the current I3I_3 is ..........

    Figure of question 46
    1. A 0.36 A
    2. B 0.96 A
    3. C -0.36 A
    4. D -0.96 A
    Solve this question →
  47. A student connected two batteries of 6 V and 12 V with negligible internal resistance, two identical ohmic resistors, two ammeters and a switch to form an electric circuit as in figure (1). Then he reversed the polarity of the 6 V battery so that the circuit became as in figure (2).
    When switch (K) is closed, what happens to the readings of the ammeters A1A_1, A2A_2 respectively:
    in the circuit of figure (1)?

    Figure of question 47
    1. A decreases, increases
    2. B decreases, does not change
    3. C does not change, decreases
    4. D increases, decreases
    Solve this question →
  48. A student connected two batteries of 6 V and 12 V with negligible internal resistance, two identical ohmic resistors, two ammeters and a switch to form an electric circuit as in figure (1). Then he reversed the polarity of the 6 V battery so that the circuit became as in figure (2).
    When switch (K) is closed, what happens to the readings of the ammeters A1A_1, A2A_2 respectively:
    in the circuit of figure (2)?

    Figure of question 48
    1. A increases, does not change
    2. B increases, increases
    3. C decreases, decreases
    4. D does not change, does not change
    Solve this question →
  49. From the opposite electric circuit:
    the potential difference between points a, b is ..........

    Figure of question 49
    1. A 1 V
    2. B 2 V
    3. C 4 V
    4. D 6 V
    Solve this question →
  50. From the opposite electric circuit:
    the emf (VB)1(V_B)_1 is ..........

    Figure of question 50
    1. A 9 V
    2. B 6 V
    3. C 4 V
    4. D 2 V
    Solve this question →
  51. From the opposite electric circuit:
    the resistance R is ..........

    Figure of question 51
    1. A 2.5 Ω
    2. B 2 Ω
    3. C 4 Ω
    4. D 7.5 Ω
    Solve this question →
  52. From the circuit shown, the ratio (VB)1(VB)2\dfrac{(V_B)_1}{(V_B)_2} is ..........

    Figure of question 52
    1. A 45\dfrac{4}{5}
    2. B 54\dfrac{5}{4}
    3. C 97\dfrac{9}{7}
    4. D 79\dfrac{7}{9}
    Solve this question →
  53. From the opposite circuit:
    the current through resistor R3R_3 is ..........

    Figure of question 53
    1. A 53\dfrac{5}{3} A
    2. B 47\dfrac{4}{7} A
    3. C 27\dfrac{2}{7} A
    4. D 49\dfrac{4}{9} A
    Solve this question →
  54. From the opposite circuit:
    the power consumed in the electric circuit is ..........

    Figure of question 54
    1. A 8.57 W
    2. B 4.42 W
    3. C 3.51 W
    4. D 2.31 W
    Solve this question →
  55. The opposite circuit contains identical cells with negligible internal resistance. Which resistance carries no electric current?

    Figure of question 55
    1. A R1R_1
    2. B R2R_2
    3. C R3R_3
    4. D R1R_1, R2R_2
    Solve this question →
  56. The opposite figure represents an electric circuit. If V2=4V1V_2 = 4 V_1, then I equals ..........

    Figure of question 56
    1. A 2 A
    2. B 4 A
    3. C 6 A
    4. D 8 A
    Solve this question →
  57. The opposite figure represents a closed electric circuit, so ..........

    Figure of question 57
    1. A Vxy>VxzV_{xy} > V_{xz}
    2. B Vxy=VxzV_{xy} = V_{xz}
    3. C Vxy<VxzV_{xy} < V_{xz}
    4. D Vxy=VyzV_{xy} = V_{yz}
    Solve this question →
  58. In the following electric circuits, all resistors are identical and all batteries are identical with negligible internal resistance. In which circuit is the reading of ammeter A1A_1 twice the reading of ammeter A2A_2?

    Figure of question 58
    1. A A
    2. B B
    3. C C
    4. D D
    Solve this question →
  59. In the electric circuit shown, the wire ab is a uniform resistance of 10 Ω and point c, where the slider touches wire ab, divides it into two resistances R1R_1, R2R_2 such that R2=1.5R1R_2 = 1.5 R_1, so:
    the current I1I_1 equals ..........

    Figure of question 59
    1. A 0.93 A
    2. B 1.09 A
    3. C 1.64 A
    4. D 2.73 A
    Solve this question →
  60. In the electric circuit shown, the wire ab is a uniform resistance of 10 Ω and point c, where the slider touches wire ab, divides it into two resistances R1R_1, R2R_2 such that R2=1.5R1R_2 = 1.5 R_1, so:
    the current I2I_2 equals ..........

    Figure of question 60
    1. A 0.93 A
    2. B 1.09 A
    3. C 1.64 A
    4. D 2.73 A
    Solve this question →
  61. In the electric circuit shown, the wire ab is a uniform resistance of 10 Ω and point c, where the slider touches wire ab, divides it into two resistances R1R_1, R2R_2 such that R2=1.5R1R_2 = 1.5 R_1, so:
    the current I equals ..........

    Figure of question 61
    1. A 0.93 A
    2. B 1.09 A
    3. C 1.64 A
    4. D 2.73 A
    Solve this question →
  62. The opposite figure represents part of an electric circuit. Using Kirchhoff's two laws and keeping to the current directions, the path and the data shown, the value of:
    the potential difference between points X, Y equals ..........

    Figure of question 62
    1. A 5 V
    2. B 7 V
    3. C 10 V
    4. D 11 V
    Solve this question →
  63. The opposite figure represents part of an electric circuit. Using Kirchhoff's two laws and keeping to the current directions, the path and the data shown, the value of:
    the emf of the battery (VB)2(V_B)_2 equals ..........

    Figure of question 63
    1. A 4 V
    2. B 8 V
    3. C 9.5 V
    4. D 11 V
    Solve this question →
  64. The opposite figure represents part of an electric circuit carrying a current of 1 A, so ..........

    Figure of question 64
    1. A potential of point A (VA)(V_A) = -1.5 V, potential of point B (VB)(V_B) = 2 V
    2. B potential of point A (VA)(V_A) = 1.5 V, potential of point B (VB)(V_B) = 2 V
    3. C potential of point A (VA)(V_A) = -1.5 V, potential of point B (VB)(V_B) = 0.5 V
    4. D potential of point A (VA)(V_A) = 1.5 V, potential of point B (VB)(V_B) = -0.5 V
    Solve this question →
  65. In the opposite electric circuit, if the reading of voltmeter V1V_1 is 21 V and the reading of voltmeter V2V_2 is 24 V, then:
    the ammeter reading is ..........

    Figure of question 65
    1. A 1 A
    2. B 2 A
    3. C 3 A
    4. D 4 A
    Solve this question →
  66. In the opposite electric circuit, if the reading of voltmeter V1V_1 is 21 V and the reading of voltmeter V2V_2 is 24 V, then:
    the resistance (R1)(R_1) equals ..........

    Figure of question 66
    1. A 2 Ω
    2. B 4 Ω
    3. C 5 Ω
    4. D 6 Ω
    Solve this question →
  67. In the opposite electric circuit, if the reading of voltmeter V1V_1 is 21 V and the reading of voltmeter V2V_2 is 24 V, then:
    the resistance (R2)(R_2) equals ..........

    Figure of question 67
    1. A 2 Ω
    2. B 4 Ω
    3. C 5 Ω
    4. D 6 Ω
    Solve this question →
  68. The following figure shows part of a circuit. If the power consumed between points a, b is 210 W and the internal resistance of the cells is negligible, then:
    the unknown emf (VB)(V_B) equals ..........

    Figure of question 68
    1. A 30 V
    2. B 20 V
    3. C 10 V
    4. D 5 V
    Solve this question →
  69. The following figure shows part of a circuit. If the power consumed between points a, b is 210 W and the internal resistance of the cells is negligible, then:
    the potential difference between points a, b equals ..........

    Figure of question 69
    1. A 20 V
    2. B 30 V
    3. C 40 V
    4. D 50 V
    Solve this question →
  70. From the electric circuit shown in the figure, the readings of the ammeter and the voltmeter are ..........

    Figure of question 70
    1. A ammeter reading 2 A, voltmeter reading 5 V
    2. B ammeter reading 1 A, voltmeter reading 5 V
    3. C ammeter reading 2 A, voltmeter reading 3 V
    4. D ammeter reading 1 A, voltmeter reading 3 V
    Solve this question →
  71. In the electric circuit shown in the figure:
    the readings of the ammeter (A) and the voltmeter (V) are ..........

    Figure of question 71
    1. A ammeter reading 0.067 A, voltmeter reading 5.6 V
    2. B ammeter reading 0.067 A, voltmeter reading 3.7 V
    3. C ammeter reading 4.067 A, voltmeter reading 5.6 V
    4. D ammeter reading 4.067 A, voltmeter reading 3.7 V
    Solve this question →
  72. In the electric circuit shown in the figure:
    the resistance R is ..........

    Figure of question 72
    1. A 11 Ω
    2. B 12 Ω
    3. C 31 Ω
    4. D 36 Ω
    Solve this question →
  73. In the opposite electric circuit, if the voltmeter reading is 6 V, then the emf (VB)(V_B) equals ..........

    Figure of question 73
    1. A 4 V
    2. B 8 V
    3. C 10 V
    4. D 12 V
    Solve this question →
  74. In the opposite electric circuit:
    the magnitude and direction of the current through the 2 Ω resistor are ..........

    Figure of question 74
    1. A 1.5 A from A to B
    2. B 1.5 A from B to A
    3. C 2.5 A from A to B
    4. D 2.5 A from B to A
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  75. In the opposite electric circuit:
    the current I1I_1 is ..........

    Figure of question 75
    1. A 1 A
    2. B 2 A
    3. C 3 A
    4. D 4 A
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  76. In the opposite electric circuit:
    the current I3I_3 is ..........

    Figure of question 76
    1. A 1.5 A
    2. B 2.5 A
    3. C 3.5 A
    4. D 4.5 A
    Solve this question →
  77. In the opposite electric circuit, if the current through resistor (R) is 1 A, then R equals ..........

    Figure of question 77
    1. A 1.5 Ω
    2. B 3 Ω
    3. C 6 Ω
    4. D 12 Ω
    Solve this question →
  78. From the circuit shown in the drawing, the total resistance of the circuit is ..........

    Figure of question 78
    1. A 0.5 Ω
    2. B 1 Ω
    3. C 1.18 Ω
    4. D 1.25 Ω
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  79. In the opposite electric circuit, what happens to the power consumed in resistor S when closing:
    only switch K1K_1?

    Figure of question 79
    1. A increases
    2. B decreases
    3. C does not change
    4. D becomes zero
    Solve this question →
  80. In the opposite electric circuit, what happens to the power consumed in resistor S when closing:
    only switch K2K_2?

    Figure of question 80
    1. A increases
    2. B decreases
    3. C does not change
    4. D becomes zero
    Solve this question →
  81. In the figure shown, 12 resistors, each R, are connected together in the form of a cube, so the equivalent resistance in terms of R is ..........

    Figure of question 81
    1. A 12\dfrac{1}{2} R
    2. B 56\dfrac{5}{6} R
    3. C 32\dfrac{3}{2} R
    4. D R
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Essay questions

  1. State the scientific principle on which each of the following is based:
    (1) Kirchhoff's first law.
    (2) Kirchhoff's second law.

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  2. The opposite figure represents part of a closed electric circuit.
    Calculate the current I2I_2

    Figure of question 2Solve this question →
  3. Calculate the currents I3I_3, I4I_4 in the opposite electric circuit.

    Figure of question 3Solve this question →
  4. From the circuit shown, calculate the current through the 3 Ω3\ \Omega resistor

    Figure of question 4Solve this question →
  5. The opposite figure represents an electric circuit. Calculate the emf of the battery (VB)(V_B), neglecting its internal resistance.

    Figure of question 5Solve this question →
  6. In the opposite electric circuit, the reading of ammeter A1A_1 is 1 A1\ A and the internal resistance of the batteries is negligible. Calculate the ratio between the readings of the two ammeters A2A3\frac{A_2}{A_3}

    Figure of question 6Solve this question →
  7. In the opposite electric circuit, prove that: V1V2=12\frac{V_1}{V_2}=\frac{1}{2}

    Figure of question 7Solve this question →
  8. The opposite figure shows part of an electric circuit. If the potential difference between points x, y is 16 V16\ V, calculate the current I

    Figure of question 8Solve this question →
  9. In the opposite electric circuit, if the internal resistance of the batteries is negligible, calculate:
    (1) the voltmeter reading (V).
    (2) the emf (VB)(V_B).

    Figure of question 9Solve this question →
  10. From the opposite circuit, calculate the current through the 12 Ω12\ \Omega resistor

    Figure of question 10Solve this question →
  11. In the opposite electric circuit, find the readings of the ammeter and the voltmeter.

    Figure of question 11Solve this question →
  12. In the opposite electric circuit, if the current (I) is the same through each of the two batteries and equals (I), find the ratio between the two resistances R1R2\frac{R_1}{R_2}

    Figure of question 12Solve this question →
  13. In the opposite circuit, calculate the current through the 10 V10\ V battery

    Figure of question 13Solve this question →
  14. The opposite figure shows an electric circuit containing identical cells with negligible internal resistance and identical lamps. Which lamp's filament glows more brightly?

    Figure of question 14Solve this question →

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From past exams

  1. In the opposite figure, applying Kirchhoff's first law at point (x) gives .......... (Trial exam / June 2021)

    Figure of question 1
    1. A I1+I3+I4+I2+I5=0I_1+I_3+I_4+I_2+I_5=0
    2. B −I1−I3−I4+I2+I5=0-I_1-I_3-I_4+I_2+I_5=0
    3. C −I1−I3+I4+I2+I5=0-I_1-I_3+I_4+I_2+I_5=0
    4. D I1+I3+I4−I2+I5=0I_1+I_3+I_4-I_2+I_5=0
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  2. From the circuit shown in the figure, .......... (2nd session 2021)

    Figure of question 2
    1. A −I1−I2+I3=0-I_1-I_2+I_3=0
    2. B I1−I2−I3=0I_1-I_2-I_3=0
    3. C −I1+I2+I3=0-I_1+I_2+I_3=0
    4. D I1+I2+I3=0I_1+I_2+I_3=0
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  3. The figure represents part of a closed electric circuit. The directions of I1I_1, I2I_2, I3I_3 are conventional current directions, while the direction of I4I_4 is the direction of motion of the free electrons, so I3I_3 = .......... (2nd session 2022)

    Figure of question 3
    1. A I1+I2−I4I_1+I_2-I_4
    2. B I1+I2+I4I_1+I_2+I_4
    3. C I4+I1−I2I_4+I_1-I_2
    4. D I4+I2−I1I_4+I_2-I_1
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  4. The figure shows part of an electric circuit, so I equals .......... (2nd session 2023)

    Figure of question 4
    1. A 11 A11\ A
    2. B 2 A2\ A
    3. C 1 A1\ A
    4. D 4 A4\ A
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  5. The opposite figure represents electric currents flowing in several branches. The value of the current (I) and the direction of the current (7 A)(7\ A) respectively are .......... (Sample exam 2025)

    Figure of question 5
    1. A 4 A4\ A, from a to d
    2. B 4 A4\ A, from d to a
    3. C 13 A13\ A, from a to d
    4. D 13 A13\ A, from d to a
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  6. In the figure, the directions shown represent the direction of electron motion. The currents in branches xa, xc, xd are 6 A6\ A, 3 A3\ A, 15 A15\ A respectively, and 2.5×10192.5\times10^{19} electrons / second pass in branch xb. The number of electrons passing through branch xf and their direction of motion are .......... (Sample exam 2025)

    Figure of question 6
    1. A 1×10201\times10^{20} electrons / second, from x to f
    2. B 1×10201\times10^{20} electrons / second, from f to x
    3. C 1.6×10191.6\times10^{19} electrons / second, from x to f
    4. D 1.6×10191.6\times10^{19} electrons / second, from f to x
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  7. Using the data written on the circuit in front of you, the ratio I2I1\frac{I_2}{I_1} equals .......... (Trial exam / May 2021)

    Figure of question 7
    1. A 21\frac{2}{1}
    2. B 31\frac{3}{1}
    3. C 12\frac{1}{2}
    4. D 13\frac{1}{3}
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  8. In the electric circuit shown, the current I3I_3 equals .......... (Trial exam / June 2021)

    Figure of question 8
    1. A 1.2 A1.2\ A
    2. B 1.25 A1.25\ A
    3. C 2 A2\ A
    4. D 2.45 A2.45\ A
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  9. In the circuit shown in the figure, Kirchhoff's laws can be applied to the closed path (adcba) as follows .......... (1st session 2021)

    Figure of question 9
    1. A 2I1+I2+4=02I_1+I_2+4=0
    2. B 2I1−I2−20=02I_1-I_2-20=0
    3. C 2I1−I2+4=02I_1-I_2+4=0
    4. D 3I1−I3−4=03I_1-I_3-4=0
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  10. In the electric circuit shown, if (I3=−2I1)(I_3=-2I_1), then the current through resistor R3R_3 equals .......... (1st session 2021)

    Figure of question 10
    1. A 37 A\frac{3}{7}\ A
    2. B 47 A\frac{4}{7}\ A
    3. C 1 A1\ A
    4. D 27 A\frac{2}{7}\ A
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  11. In the circuit shown, if I3I_3 equals 2 A2\ A, then I2I_2 equals .......... (2nd session 2021)

    Figure of question 11
    1. A 1 A1\ A
    2. B 2 A2\ A
    3. C 3 A3\ A
    4. D 4 A4\ A
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  12. In the electric circuit shown in the figure, if the ammeter reading is zero, then (VB)2(V_B)_2 equals .......... (1st session 2022)

    Figure of question 12
    1. A 6 V6\ V
    2. B 4.5 V4.5\ V
    3. C 8 V8\ V
    4. D 12 V12\ V
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  13. In the circuit shown, the current through the 8 Ω8\ \Omega resistor equals .......... (1st session 2022)

    Figure of question 13
    1. A 0.23 A0.23\ A
    2. B 0.846 A0.846\ A
    3. C 1.077 A1.077\ A
    4. D 1.306 A1.306\ A
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  14. In the electric circuit shown, the value of VBV_B equals .......... (2nd session 2022)

    Figure of question 14
    1. A 10 V10\ V
    2. B 4 V4\ V
    3. C 15 V15\ V
    4. D 6 V6\ V
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  15. In the circuit shown in the figure, the emf (VB)(V_B) is .......... (Trial exam 2023)

    Figure of question 15
    1. A 12 V12\ V
    2. B 43 V\frac{4}{3}\ V
    3. C 403 V\frac{40}{3}\ V
    4. D 443 V\frac{44}{3}\ V
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  16. You have an electric circuit as in the figure, so the ratio I3I2\frac{I_3}{I_2} equals .......... (1st session 2023)

    Figure of question 16
    1. A 21\frac{2}{1}
    2. B 14\frac{1}{4}
    3. C 12\frac{1}{2}
    4. D 41\frac{4}{1}
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  17. The figure in front of you represents part of a closed electric circuit, so the resistance R equals .......... (2nd session 2023)

    Figure of question 17
    1. A 4 Ω4\ \Omega
    2. B 2 Ω2\ \Omega
    3. C 6 Ω6\ \Omega
    4. D 3 Ω3\ \Omega
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  18. You have an electric circuit as in the figure, so the relation between the two currents I1I_1, I3I_3 is .......... (1st session 2024)

    Figure of question 18
    1. A I1=2.25I3I_1=2.25I_3
    2. B I1=1.25I3I_1=1.25I_3
    3. C I1=0.8I3I_1=0.8I_3
    4. D I1=1.8I3I_1=1.8I_3
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  19. The opposite figure shows part of an electric circuit. Using Kirchhoff's two laws, which of the following equations is correct? (2nd session 2024)

    Figure of question 19
    1. A 3I1+7I2=−3VB3I_1+7I_2=-3V_B
    2. B 3I2−5I3=−3VB3I_2-5I_3=-3V_B
    3. C 3I2−5I3=3VB3I_2-5I_3=3V_B
    4. D 3I1−8I2=3VB3I_1-8I_2=3V_B
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  20. The opposite figure represents part of an electric circuit carrying an electric current, so the value of VBV_B is .......... (Sample exam 2025)

    Figure of question 20
    1. A 30 V30\ V
    2. B 25 V25\ V
    3. C 20 V20\ V
    4. D 15 V15\ V
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  21. In the electric circuit shown in the figure, what are the values of (VB)(V_B) and (R)(R)? (1st session 2025)

    Figure of question 21
    1. A VB=30 VV_B=30\ V, R=40 ΩR=40\ \Omega
    2. B VB=20 VV_B=20\ V, R=30 ΩR=30\ \Omega
    3. C VB=30 VV_B=30\ V, R=20 ΩR=20\ \Omega
    4. D VB=20 VV_B=20\ V, R=40 ΩR=40\ \Omega
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  22. In the electric circuit shown in the figure, what are the values of (I1)(I_1) and (I2)(I_2)? (2nd session 2025)

    Figure of question 22
    1. A I1=0.215 AI_1=0.215\ A, I2=0.447 AI_2=0.447\ A
    2. B I1=0.215 AI_1=0.215\ A, I2=0.232 AI_2=0.232\ A
    3. C I1=0.232 AI_1=0.232\ A, I2=0.132 AI_2=0.132\ A
    4. D I1=0.232 AI_1=0.232\ A, I2=0.215 AI_2=0.215\ A
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  23. The opposite figure represents part of an electric circuit. If the potential difference between points A, B is 16 V16\ V, then the current through the 2 Ω2\ \Omega resistor equals .......... (Sample exam 2026)

    Figure of question 23
    1. A 2.5 A2.5\ A
    2. B 3.5 A3.5\ A
    3. C 4 A4\ A
    4. D zero
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